log10(n);
| Argument | Description |
|---|---|
| n | The input value. |
Returns: Real
This function is similar to the log2(n) function, only that
log10(n) gets the number of 10's that we need to multiply
together to get n. So log10(100) returns 2, as multiplying
10 by itself gives 100, log10(1000) returns 3 as
10x10x10=1000 etc... The number does not have to be
divisible by ten, however, but this will still return an
appropriate value, for example if we have log10(101) we
get 2.00432137... which is how many times you could divide 101 by
10.
logval = log10(num);
The above code gets the log10 of the value stored in "num".